If omega=(-1+i sqrt(3))/(2) then (3+omeg...

If `omega=(-1+i sqrt(3))/(2)` then `(3+omega+3 omega^(2))^(4)=`

A

`16omega`

B

`16omega^2`

C

16

D

`-16`

Verified by Experts

The correct Answer is:

A

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