If the cube root of unity are 1,omega,om...

If the cube root of unity are `1,omega,omega^(2)`, then the roots of the equation `(x-1)^(3)+8=0` are :

A

`-1.1+2omega,1+2omega^2`

B

`-1,1-2omega,1-2omega^2`

C

`-1,-1,-1`

D

`-1,-1+2 omega,-1-2omega^2`

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The correct Answer is:

B

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