Let Delta=|(1,sintheta,1),(-sin theta,1,...

Let `Delta=|(1,sintheta,1),(-sin theta,1,sintheta),(-1,-sintheta,1)|` , then `Delta` lies in the interval.

A

[2,4]

B

[2,3]

C

[3,4]

D

(2,4)

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The correct Answer is:

A

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