Inverse of the matrix [[cos 2 theta,-sin...

Inverse of the matrix `[[cos 2 theta,-sin 2 theta],[sin 2 theta , cos 2 theta]]` is

A

`[(cos 2 theta, sin 2theta),(sin 2 theta,cos 2 theta)]`

B

`[(cos 2 theta, sin 2theta),(-sin 2 theta,cos 2 theta)]`

C

`[(cos 2 theta,- sin 2theta),(sin 2 theta,cos 2 theta)]`

D

`[(cos 2 theta, sin 2theta),(sin 2 theta,-cos 2 theta)]`

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The correct Answer is:

B

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