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int sec^(2)x. cosec^(2)x dx...

`int sec^(2)x. cosec^(2)x dx`

A

`tanx.cotx+c`

B

`tanx+cotx+c`

C

`tanx-cotx+c`

D

`(tanx)/(cotx)+c`

Text Solution

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The correct Answer is:
C
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