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int (cos4x+1)/(cotx-tanx) dx = A cos 4x ...

`int (cos4x+1)/(cotx-tanx) dx = A cos 4x + B`then

A

`1/8 cos4x+c`

B

`1/4 cos4x+c`

C

`-1/4 cos4x+c`

D

`-1/8 cos4x+c`

Text Solution

Verified by Experts

The correct Answer is:
D
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