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underset(0)overset(pi)intxf(sin x)dx=A u...

`underset(0)overset(pi)intxf(sin x)dx=A underset(0)overset(pi//2)int f(sin x) dx` then A is

A

`piunderset(0)overset(pi)intf(sinx)dx`

B

`pi/2underset(0)overset(pi//2)intf(sinx)dx`

C

`piunderset(0)overset(pi//2)intf(cosx)dx`

D

`piunderset(0)overset(pi)intf(cosx)dx`

Text Solution

Verified by Experts

The correct Answer is:
C
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