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The derivative of e^(ax) cosbx with resp...

The derivative of `e^(ax)` cosbx with respect to x is `re^(ax)" "cos(bx+tan^(-1)(b)/(a))`. When `agt0,bgt0`, the value of r is

A

ab

B

`a+b`

C

`sqrt(a^2+b^2)`

D

`1/(sqrt(ab))`

Text Solution

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The correct Answer is:
C
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