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A man travels 35km partly at 4 km/hr and...

A man travels 35km partly at 4 km/hr and at 5 km/hr if he cover former distance at 5km/hr and later distance at 4 km/hr, he could cover 2 km more in the same time the time taken to cover the whole distance at original rate is

A

9 hours

B

7 hours

C

(4)1/2 hours

D

8 hours

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the time taken by the man to travel a total distance of 35 km at two different speeds. We will break down the distance into two parts, one part traveled at 4 km/hr and the other at 5 km/hr. ### Step-by-Step Solution: 1. **Let the distances be defined**: - Let the distance traveled at 5 km/hr be \( x \) km. - Therefore, the distance traveled at 4 km/hr will be \( (35 - x) \) km. 2. **Set up the time equations**: - The time taken to travel \( x \) km at 5 km/hr is given by: \[ \text{Time}_1 = \frac{x}{5} \] - The time taken to travel \( (35 - x) \) km at 4 km/hr is given by: \[ \text{Time}_2 = \frac{35 - x}{4} \] 3. **Total time for the original journey**: - The total time taken for the journey at the original speeds is: \[ \text{Total Time} = \frac{x}{5} + \frac{35 - x}{4} \] 4. **Consider the alternative scenario**: - If the man travels the first part at 4 km/hr and the second part at 5 km/hr, the distances remain the same: - The time taken to travel \( x \) km at 4 km/hr is: \[ \text{Time}_1' = \frac{x}{4} \] - The time taken to travel \( (35 - x) \) km at 5 km/hr is: \[ \text{Time}_2' = \frac{35 - x}{5} \] 5. **Total time for the alternative journey**: - The total time taken for this journey is: \[ \text{Total Time}' = \frac{x}{4} + \frac{35 - x}{5} \] 6. **Set up the equation based on the problem statement**: - According to the problem, in the alternative scenario, he could cover 2 km more in the same time: \[ \text{Total Time} = \text{Total Time}' \quad \text{(for 35 km)} \quad \text{and} \quad \text{Total Time}' \quad \text{(for 37 km)} \] - Therefore, we can set up the equation: \[ \frac{x}{5} + \frac{35 - x}{4} = \frac{x}{4} + \frac{37 - x}{5} \] 7. **Solve the equation**: - To solve this equation, first find a common denominator, which is 20: \[ \frac{4x}{20} + \frac{5(35 - x)}{20} = \frac{5x}{20} + \frac{4(37 - x)}{20} \] - Simplifying gives: \[ 4x + 175 - 5x = 5x + 148 - 4x \] - Rearranging terms leads to: \[ 175 - 5x = 148 + x \] - Solving for \( x \): \[ 175 - 148 = 5x + x \implies 27 = 6x \implies x = \frac{27}{6} = 4.5 \text{ km} \] 8. **Find the other distance**: - The distance traveled at 4 km/hr is: \[ 35 - x = 35 - 4.5 = 30.5 \text{ km} \] 9. **Calculate total time at original rates**: - Now we can calculate the total time taken at the original rates: \[ \text{Total Time} = \frac{4.5}{5} + \frac{30.5}{4} \] - Calculating each part: \[ \text{Total Time} = 0.9 + 7.625 = 8.525 \text{ hours} \] ### Final Answer: The time taken to cover the whole distance at the original rate is approximately **8.525 hours**.
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