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A train leaves Delhi at 5 a.m. and reach...

A train leaves Delhi at 5 a.m. and reaches Kanpur at 10 a.m. Another train leaves Kanpur at 7 a.m. and reaches Delhi at 2 p.m. At what time do the two trains meet?

A

8.45am

B

3.45p.m

C

6.45a.m

D

data inadequate

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AI Generated Solution

The correct Answer is:
To solve the problem of when the two trains meet, we can follow these steps: ### Step 1: Determine the distance between Delhi and Kanpur Let's assume the distance between Delhi and Kanpur is \( D \) kilometers. For simplicity, we will use \( D = 35 \) km as suggested in the transcript. ### Step 2: Calculate the speed of the first train The first train leaves Delhi at 5 a.m. and reaches Kanpur at 10 a.m. This means it takes 5 hours to cover the distance of 35 km. \[ \text{Speed of first train} = \frac{\text{Distance}}{\text{Time}} = \frac{35 \text{ km}}{5 \text{ hours}} = 7 \text{ km/h} \] ### Step 3: Calculate the speed of the second train The second train leaves Kanpur at 7 a.m. and reaches Delhi at 2 p.m. This means it takes 7 hours to cover the same distance of 35 km. \[ \text{Speed of second train} = \frac{\text{Distance}}{\text{Time}} = \frac{35 \text{ km}}{7 \text{ hours}} = 5 \text{ km/h} \] ### Step 4: Set up the equation for the meeting point Let \( t \) be the time in hours after 5 a.m. when the two trains meet. - The distance covered by the first train after \( t \) hours is \( 7t \) km. - The second train starts at 7 a.m., which is 2 hours after the first train has started. Therefore, it travels for \( t - 2 \) hours (only if \( t \) is greater than 2) and covers a distance of \( 5(t - 2) \) km. At the meeting point, the total distance covered by both trains will equal the distance between Delhi and Kanpur: \[ 7t + 5(t - 2) = 35 \] ### Step 5: Solve the equation Expanding the equation: \[ 7t + 5t - 10 = 35 \] \[ 12t - 10 = 35 \] \[ 12t = 45 \] \[ t = \frac{45}{12} = 3.75 \text{ hours} \] ### Step 6: Determine the meeting time Since \( t = 3.75 \) hours after 5 a.m., we can convert this into hours and minutes: \[ 3.75 \text{ hours} = 3 \text{ hours} + 0.75 \text{ hours} = 3 \text{ hours} + 45 \text{ minutes} \] Adding this to 5 a.m.: \[ 5:00 \text{ a.m.} + 3 \text{ hours} + 45 \text{ minutes} = 8:45 \text{ a.m.} \] ### Conclusion The two trains meet at **8:45 a.m.** ---
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