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A park is in the form of a one square on...

A park is in the form of a one square one of the whose sides is 100 m . The area of the park excluding the circular lawn in the centre of the park is `8614 m^2` .The radius of the circular lawn is -----

A

21 m

B

31 m

C

41 m

D

None of these

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The correct Answer is:
To find the radius of the circular lawn in the park, we can follow these steps: ### Step 1: Calculate the area of the square park. The area of a square is given by the formula: \[ \text{Area} = \text{side}^2 \] Given that the side of the square park is 100 m, we can calculate: \[ \text{Area of the park} = 100^2 = 10000 \, \text{m}^2 \] ### Step 2: Set up the equation for the area excluding the circular lawn. We know that the area of the park excluding the circular lawn is given as \(8614 \, \text{m}^2\). Therefore, we can set up the equation: \[ \text{Area of the park} - \text{Area of the circular lawn} = 8614 \] Substituting the area of the park: \[ 10000 - \text{Area of the circular lawn} = 8614 \] ### Step 3: Solve for the area of the circular lawn. Rearranging the equation gives: \[ \text{Area of the circular lawn} = 10000 - 8614 = 1386 \, \text{m}^2 \] ### Step 4: Use the area of the circular lawn to find the radius. The area of a circle is given by the formula: \[ \text{Area} = \pi r^2 \] Substituting the area of the circular lawn: \[ \pi r^2 = 1386 \] Using \( \pi \approx \frac{22}{7} \), we can rewrite the equation: \[ \frac{22}{7} r^2 = 1386 \] ### Step 5: Solve for \( r^2 \). Multiplying both sides by \( \frac{7}{22} \) to isolate \( r^2 \): \[ r^2 = 1386 \times \frac{7}{22} \] ### Step 6: Calculate \( r^2 \). Calculating the right side: \[ r^2 = 1386 \times \frac{7}{22} = \frac{1386 \times 7}{22} = \frac{9702}{22} = 441 \] ### Step 7: Find \( r \). Taking the square root of both sides: \[ r = \sqrt{441} = 21 \, \text{m} \] ### Final Answer: The radius of the circular lawn is \( 21 \, \text{m} \). ---
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