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Radhika runs along the boundary of a rec...

Radhika runs along the boundary of a rectangular park at the rate of 12 km/hr and completes one full round in 15 minutes.If the length of the park is 4 times its breadth , the area of the park is -----

A

A)`360000 m^2`

B

B)`36000 m^2`

C

C)`3600 m^2`

D

D)None of these

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The correct Answer is:
To solve the problem step by step, we will follow the information provided in the question and use the relationships between the dimensions of the rectangular park. ### Step 1: Determine the distance Radhika runs in one round Radhika runs at a speed of 12 km/hr and completes one round in 15 minutes. First, we need to convert the time from minutes to hours. \[ \text{Time in hours} = \frac{15 \text{ minutes}}{60} = \frac{1}{4} \text{ hours} \] Now, we can calculate the distance she runs in one round using the formula: \[ \text{Distance} = \text{Speed} \times \text{Time} \] Substituting the values: \[ \text{Distance} = 12 \text{ km/hr} \times \frac{1}{4} \text{ hr} = 3 \text{ km} \] ### Step 2: Relate the distance to the perimeter of the park The distance Radhika runs in one round is equal to the perimeter of the rectangular park. The perimeter \( P \) of a rectangle is given by: \[ P = 2(\text{Length} + \text{Breadth}) \] Let the breadth be \( k \) meters. Since the length is 4 times the breadth, the length will be \( 4k \) meters. Therefore, the perimeter can be expressed as: \[ P = 2(k + 4k) = 2(5k) = 10k \] Setting this equal to the distance Radhika runs: \[ 10k = 3 \text{ km} = 3000 \text{ meters} \] ### Step 3: Solve for the breadth \( k \) Now we can solve for \( k \): \[ k = \frac{3000 \text{ meters}}{10} = 300 \text{ meters} \] ### Step 4: Calculate the length of the park Since the length is 4 times the breadth: \[ \text{Length} = 4k = 4 \times 300 = 1200 \text{ meters} \] ### Step 5: Calculate the area of the park The area \( A \) of a rectangle is given by: \[ A = \text{Length} \times \text{Breadth} \] Substituting the values we found: \[ A = 1200 \text{ meters} \times 300 \text{ meters} = 360000 \text{ square meters} \] ### Conclusion The area of the park is: \[ \text{Area} = 360000 \text{ square meters} \]
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