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1/(sqrt9-sqrt8)=?...

`1/(sqrt9-sqrt8)=?`

A

`1/2(3-2sqrt2)`

B

`1/(3+2sqrt2)`

C

`(3-2sqrt2)`

D

`(3+2sqrt2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \( \frac{1}{\sqrt{9} - \sqrt{8}} \), we can follow these steps: ### Step 1: Simplify the square roots First, we simplify the square roots in the expression: \[ \sqrt{9} = 3 \quad \text{and} \quad \sqrt{8} = \sqrt{4 \cdot 2} = 2\sqrt{2} \] So, we rewrite the expression: \[ \frac{1}{\sqrt{9} - \sqrt{8}} = \frac{1}{3 - 2\sqrt{2}} \] ### Step 2: Rationalize the denominator To eliminate the square root from the denominator, we multiply the numerator and the denominator by the conjugate of the denominator, which is \( 3 + 2\sqrt{2} \): \[ \frac{1}{3 - 2\sqrt{2}} \cdot \frac{3 + 2\sqrt{2}}{3 + 2\sqrt{2}} = \frac{3 + 2\sqrt{2}}{(3 - 2\sqrt{2})(3 + 2\sqrt{2})} \] ### Step 3: Calculate the denominator Now we calculate the denominator using the difference of squares: \[ (3 - 2\sqrt{2})(3 + 2\sqrt{2}) = 3^2 - (2\sqrt{2})^2 = 9 - 8 = 1 \] ### Step 4: Simplify the expression Now, we can simplify the expression: \[ \frac{3 + 2\sqrt{2}}{1} = 3 + 2\sqrt{2} \] ### Final Answer Thus, the final answer is: \[ \frac{1}{\sqrt{9} - \sqrt{8}} = 3 + 2\sqrt{2} \] ---
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