Home
Class 14
MATHS
(69-14xx3+2)/(9xx5-(5)^2)=?...

`(69-14xx3+2)/(9xx5-(5)^2)=?`

A

1.45

B

2.75

C

26.5

D

265

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \((69 - 14 \times 3 + 2) / (9 \times 5 - (5)^2)\), we will follow these steps: ### Step 1: Simplify the Numerator The numerator is \(69 - 14 \times 3 + 2\). 1. Calculate \(14 \times 3\): \[ 14 \times 3 = 42 \] 2. Substitute back into the numerator: \[ 69 - 42 + 2 \] 3. Perform the subtraction and addition: \[ 69 - 42 = 27 \] \[ 27 + 2 = 29 \] So, the numerator simplifies to \(29\). ### Step 2: Simplify the Denominator The denominator is \(9 \times 5 - (5)^2\). 1. Calculate \(9 \times 5\): \[ 9 \times 5 = 45 \] 2. Calculate \((5)^2\): \[ (5)^2 = 25 \] 3. Substitute back into the denominator: \[ 45 - 25 \] 4. Perform the subtraction: \[ 45 - 25 = 20 \] So, the denominator simplifies to \(20\). ### Step 3: Divide the Numerator by the Denominator Now we have: \[ \frac{29}{20} \] ### Final Result The simplified expression is: \[ \frac{29}{20} \]
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • SIMPLE INTEREST

    UPKAR PUBLICATION |Exercise QUESTION BANK|55 Videos
  • SQUARE ROOT AND CUBE ROOT

    UPKAR PUBLICATION |Exercise QUESTION BANK|76 Videos

Similar Questions

Explore conceptually related problems

(5^(n+3) -6xx5^(n+1))/(9xx5^n-5^nxx2^2)=?

Evaluate: (i) ((5)/(9)) ^(-2) xx ((3)/(5)) ^(-3) xx ((3)/(5)) ^(0) (ii) ((-3)/(5)) ^(-4) xx ((-2)/(5))^(2) (iii) ((-2)/(3)) ^(-3) xx ((-2)/(3)) ^(-2)

Knowledge Check

  • (4^(5)xx3^5)/((12)^(5) xx9^2)= ?

    A
    `3^(2)xx2^5`
    B
    `(1)/(3^4)`
    C
    `12`
    D
    `(1)/(4^3)`
  • Find (-4)/(5)xx(3)/(7)xx(15)/(16)xx((-14)/(9))

    A
    `2/6`
    B
    `2/8`
    C
    `2/10`
    D
    `1/2`
  • Find the value of the expression (3)/(5) xx (3)/(14) xx (15)/(2) xx (-7)/(9).

    A
    `(-7)/(8)`
    B
    `(-5)/(6)`
    C
    `(-3)/(4)`
    D
    `(-3)/(5)`
  • Similar Questions

    Explore conceptually related problems

    Name the property of multiplication illustrated by the following statements: (i) (-15)/(8)xx(-12)/(7) = (-12)/(7)xx (-15)/(8) (ii) ((-2)/(3) xx (7)/(9)) xx (-9)/(5) = (-2)/(3)xx ((7)/(9)xx (-9)/(5)) (iii) (-3)/(4) xx ((-5)/(6)+(7)/(8))= ((-3)/(4)xx (-5)/(6))+((-3)/(4)xx (7)/(8)) (iv) (-16)/(9) xx 1 = 1 xx (-16)/(9) = (-16)/(9) (v) (-11)/(15)xx (15)/(-11) =(15)/(-11)xx (-11)/(15) = 1 (vi) (-7)/(5) xx 0 =0

    Simplify : (((2)/(3)xx (-(5)/(4)))+((-(10)/(3)) xx (5)/(2))-(((-16)/(3))xx(-(55)/(32))))/((3)/(2)xx((-(9)/(14))xx(-(1)/(7))))

    Simplify: (a) 108-:36 of (1)/(4)+(2)/(5)xx3(1)/(4) (b) (2)/(3)xx(5)/(6)+(4)/(9)-(3)/(4)+(2)/(9)xx(5)/(9)-:(2)/(9)

    Using appropriate properties find.(i) -(2)/(5)xx(3)/(5)+(5)/(2)-(3)/(5)xx(1)/(6)( ii) (2)/(5)xx(-(3)/(7))^(2)-(1)/(6)xx(3)/(2)+(1)/(14)xx(2)/(5)

    Simplify : (5^(n+4)-6xx5^(n+2))/(9xx5^(n+1)-5^(n+1)xx4)