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1/(1.2.3)+1/(2.3.4)+1/(3.4.5)+1/(4.5.6)i...

`1/(1.2.3)+1/(2.3.4)+1/(3.4.5)+1/(4.5.6)`is equal to

A

A)(7/30)

B

B)(11/30)

C

C)(13/30)

D

D)(17/30)

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \( \frac{1}{1 \cdot 2 \cdot 3} + \frac{1}{2 \cdot 3 \cdot 4} + \frac{1}{3 \cdot 4 \cdot 5} + \frac{1}{4 \cdot 5 \cdot 6} \), we will follow these steps: ### Step 1: Calculate each term's denominator We first calculate the denominators for each term: - \( 1 \cdot 2 \cdot 3 = 6 \) - \( 2 \cdot 3 \cdot 4 = 24 \) - \( 3 \cdot 4 \cdot 5 = 60 \) - \( 4 \cdot 5 \cdot 6 = 120 \) ### Step 2: Rewrite the expression Now we can rewrite the expression with the calculated denominators: \[ \frac{1}{6} + \frac{1}{24} + \frac{1}{60} + \frac{1}{120} \] ### Step 3: Find the least common multiple (LCM) Next, we find the least common multiple (LCM) of the denominators \( 6, 24, 60, \) and \( 120 \). The LCM is \( 120 \). ### Step 4: Rewrite each fraction with the LCM as the denominator Now we convert each fraction to have a denominator of \( 120 \): - For \( \frac{1}{6} \): \[ \frac{1}{6} = \frac{20}{120} \quad \text{(since \( 120 \div 6 = 20 \))} \] - For \( \frac{1}{24} \): \[ \frac{1}{24} = \frac{5}{120} \quad \text{(since \( 120 \div 24 = 5 \))} \] - For \( \frac{1}{60} \): \[ \frac{1}{60} = \frac{2}{120} \quad \text{(since \( 120 \div 60 = 2 \))} \] - For \( \frac{1}{120} \): \[ \frac{1}{120} = \frac{1}{120} \] ### Step 5: Combine the fractions Now we can combine all the fractions: \[ \frac{20}{120} + \frac{5}{120} + \frac{2}{120} + \frac{1}{120} = \frac{20 + 5 + 2 + 1}{120} = \frac{28}{120} \] ### Step 6: Simplify the fraction Now we simplify \( \frac{28}{120} \): - The greatest common divisor (GCD) of \( 28 \) and \( 120 \) is \( 4 \). - Dividing both the numerator and the denominator by \( 4 \): \[ \frac{28 \div 4}{120 \div 4} = \frac{7}{30} \] ### Final Answer Thus, the final answer is: \[ \frac{7}{30} \]
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UPKAR PUBLICATION -SIMPLIFICATION-QUESTION BANK
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  10. (1/4+1/4div5/4)/(1/4xx1/4+(2)1/4=?

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