The price of a scooter and television set are in ratio 3:2 if a scooter costs Rs.6000more than the television set the price of the television set is

Options

A. Rs.6000
B. Rs.10000
C. Rs.12000
D. Rs.18000

Answer

To solve the problem, we need to find the price of the television set given the ratio of the prices of the scooter and television, and the additional information that the scooter costs Rs. 6000 more than the television.

### Step-by-Step Solution:

1. **Define Variables**:
Let the price of the television set be \( T \) and the price of the scooter be \( S \).

2. **Set Up the Ratio**:
According to the problem, the prices are in the ratio of 3:2. This can be expressed as:
\[ \frac{S}{T} = \frac{3}{2} \]
From this ratio, we can express the price of the scooter in terms of the price of the television:
\[ S = \frac{3}{2}T \]

3. **Use the Given Information**:
We know that the scooter costs Rs. 6000 more than the television. This can be written as:
\[ S = T + 6000 \]

4. **Set Up the Equation**:
Now we have two expressions for \( S \):
\[ \frac{3}{2}T = T + 6000 \]

5. **Solve for \( T \)**:
To eliminate the fraction, multiply every term by 2:
\[ 3T = 2T + 12000 \]
Now, subtract \( 2T \) from both sides:
\[ 3T - 2T = 12000 \]
This simplifies to:
\[ T = 12000 \]

6. **Conclusion**:
The price of the television set is Rs. 12000.

### Final Answer:
The price of the television set is Rs. 12000.