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The largest number which exactly divide...

The largest number which exactly divides 210, 315, 147 and 168 is -

A

3

B

7

C

21

D

4410

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The correct Answer is:
To find the largest number that exactly divides 210, 315, 147, and 168, we will calculate the Highest Common Factor (HCF) using the prime factorization method. Here are the steps: ### Step 1: Prime Factorization of Each Number 1. **Factor 210**: - 210 can be divided by 2: \( 210 \div 2 = 105 \) - 105 can be divided by 3: \( 105 \div 3 = 35 \) - 35 can be divided by 5: \( 35 \div 5 = 7 \) - 7 is a prime number. - Therefore, the prime factorization of 210 is: \[ 210 = 2^1 \times 3^1 \times 5^1 \times 7^1 \] 2. **Factor 315**: - 315 can be divided by 3: \( 315 \div 3 = 105 \) - 105 can be divided by 3 again: \( 105 \div 3 = 35 \) - 35 can be divided by 5: \( 35 \div 5 = 7 \) - 7 is a prime number. - Therefore, the prime factorization of 315 is: \[ 315 = 3^2 \times 5^1 \times 7^1 \] 3. **Factor 147**: - 147 can be divided by 3: \( 147 \div 3 = 49 \) - 49 can be divided by 7: \( 49 \div 7 = 7 \) - 7 is a prime number. - Therefore, the prime factorization of 147 is: \[ 147 = 3^1 \times 7^2 \] 4. **Factor 168**: - 168 can be divided by 2: \( 168 \div 2 = 84 \) - 84 can be divided by 2: \( 84 \div 2 = 42 \) - 42 can be divided by 2: \( 42 \div 2 = 21 \) - 21 can be divided by 3: \( 21 \div 3 = 7 \) - 7 is a prime number. - Therefore, the prime factorization of 168 is: \[ 168 = 2^3 \times 3^1 \times 7^1 \] ### Step 2: Identify Common Factors Now, we will identify the common prime factors from the factorizations we obtained: - **For 2**: - 210: \( 2^1 \) - 315: \( 2^0 \) (not present) - 147: \( 2^0 \) (not present) - 168: \( 2^3 \) - **Common factor**: \( 2^0 \) (not included in HCF) - **For 3**: - 210: \( 3^1 \) - 315: \( 3^2 \) - 147: \( 3^1 \) - 168: \( 3^1 \) - **Common factor**: \( 3^1 \) - **For 5**: - 210: \( 5^1 \) - 315: \( 5^1 \) - 147: \( 5^0 \) (not present) - 168: \( 5^0 \) (not present) - **Common factor**: \( 5^0 \) (not included in HCF) - **For 7**: - 210: \( 7^1 \) - 315: \( 7^1 \) - 147: \( 7^2 \) - 168: \( 7^1 \) - **Common factor**: \( 7^1 \) ### Step 3: Calculate HCF Now we multiply the common factors: \[ \text{HCF} = 3^1 \times 7^1 = 3 \times 7 = 21 \] ### Final Answer The largest number that exactly divides 210, 315, 147, and 168 is **21**. ---
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