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The numbers of prime factors in 2^(222)x...

The numbers of prime factors in `2^(222)xx3^(333)xx5^(555)` is-

A

3

B

1107

C

1110

D

1272

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AI Generated Solution

The correct Answer is:
To find the number of prime factors in the expression \(2^{222} \times 3^{333} \times 5^{555}\), we can follow these steps: ### Step 1: Identify the prime factors The expression consists of three prime factors: \(2\), \(3\), and \(5\). ### Step 2: Count the occurrences of each prime factor - The prime factor \(2\) appears \(222\) times. - The prime factor \(3\) appears \(333\) times. - The prime factor \(5\) appears \(555\) times. ### Step 3: Calculate the total number of prime factors To find the total number of prime factors, we add the occurrences of each prime factor: \[ 222 + 333 + 555 \] ### Step 4: Perform the addition Now, we calculate the sum: \[ 222 + 333 = 555 \] \[ 555 + 555 = 1110 \] ### Final Answer Thus, the total number of prime factors in the expression \(2^{222} \times 3^{333} \times 5^{555}\) is \(1110\). ---
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