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8 men entered a lounge simultaneously . ...

8 men entered a lounge simultaneously . if each peron shook hands with the other, then find the total no. of hand shakes.

A

16

B

36

C

56

D

28

Text Solution

AI Generated Solution

The correct Answer is:
To find the total number of handshakes among 8 men, we can use the concept of combinations. When each person shakes hands with every other person, we can determine the total number of unique handshakes using the formula for combinations. ### Step-by-Step Solution: 1. **Understanding the Problem**: We have 8 men, and each man shakes hands with every other man. We need to find the total number of unique handshakes. 2. **Identifying the Formula**: The number of ways to choose 2 people from a group of n people (which represents a handshake between two people) is given by the combination formula: \[ C(n, 2) = \frac{n!}{2!(n-2)!} \] where \( n \) is the total number of people. 3. **Substituting the Values**: Here, \( n = 8 \). So we substitute 8 into the formula: \[ C(8, 2) = \frac{8!}{2!(8-2)!} = \frac{8!}{2! \cdot 6!} \] 4. **Calculating Factorials**: We can simplify this calculation: \[ C(8, 2) = \frac{8 \times 7}{2 \times 1} = \frac{56}{2} = 28 \] 5. **Conclusion**: Therefore, the total number of unique handshakes that occur when 8 men each shake hands with every other man is **28**. ### Final Answer: The total number of handshakes is **28**.
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