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A sum of money put at simple interest tr...

A sum of money put at simple interest trebles itself in 15 years. The rate per cent per annum is

A

`13 1/3`

B

`16 2/3`

C

`12 2/3`

D

`20%`

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AI Generated Solution

The correct Answer is:
To find the rate of simple interest at which a sum of money triples itself in 15 years, we can follow these steps: ### Step 1: Understand the Problem We know that a sum of money triples itself in 15 years. This means if we start with a principal amount \( P \), after 15 years, the amount \( A \) will be \( 3P \). ### Step 2: Calculate the Simple Interest The simple interest (SI) can be calculated using the formula: \[ SI = A - P \] Substituting the values we have: \[ SI = 3P - P = 2P \] ### Step 3: Use the Simple Interest Formula The formula for simple interest is: \[ SI = \frac{P \times R \times T}{100} \] Where: - \( P \) = Principal amount - \( R \) = Rate of interest per annum - \( T \) = Time in years ### Step 4: Substitute Known Values From the previous steps, we know: - \( SI = 2P \) - \( T = 15 \) years Substituting these into the simple interest formula gives: \[ 2P = \frac{P \times R \times 15}{100} \] ### Step 5: Simplify the Equation We can cancel \( P \) from both sides (assuming \( P \neq 0 \)): \[ 2 = \frac{R \times 15}{100} \] ### Step 6: Solve for \( R \) To isolate \( R \), we multiply both sides by 100: \[ 200 = R \times 15 \] Now, divide both sides by 15: \[ R = \frac{200}{15} \] ### Step 7: Simplify the Rate Calculating \( \frac{200}{15} \): \[ R = \frac{40}{3} \approx 13.33\% \] This can also be expressed as \( 13 \frac{1}{3}\% \). ### Conclusion Thus, the rate of interest per annum is \( 13 \frac{1}{3}\% \). ---
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UPKAR PUBLICATION -SIMPLE INTEREST -QUESTION BANK
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