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If the rate of interest rises from 6 1/...

If the rate of interest rises from `6 1/2` to `8%` a man's annual income increases by Rs. 4050. Find the capital.

A

Rs. 270000

B

Rs. 370000

C

Rs. 300000

D

None of these

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The correct Answer is:
To solve the problem step by step, we will follow these calculations: ### Step 1: Convert the mixed fraction to an improper fraction The rate of interest rises from \(6 \frac{1}{2}\%\) to \(8\%\). First, we need to convert \(6 \frac{1}{2}\%\) into a decimal or improper fraction. \[ 6 \frac{1}{2} = 6 + \frac{1}{2} = \frac{12}{2} + \frac{1}{2} = \frac{13}{2}\% \] ### Step 2: Calculate the increase in interest rate Now, we find the increase in the interest rate: \[ \text{Increase in interest rate} = 8\% - 6 \frac{1}{2}\% = 8\% - \frac{13}{2}\% = \frac{16}{2}\% - \frac{13}{2}\% = \frac{3}{2}\% \] ### Step 3: Convert the percentage increase to a decimal Next, we convert \(\frac{3}{2}\%\) into a decimal for easier calculations: \[ \frac{3}{2}\% = \frac{3}{2} \times \frac{1}{100} = \frac{3}{200} = 0.015 \] ### Step 4: Relate the increase in income to the capital The increase in annual income due to the rise in interest rate is given as Rs. 4050. We can express this relationship using the formula for simple interest: \[ \text{Increase in income} = \text{Capital} \times \text{Increase in interest rate} \] Let \(C\) be the capital. Then, we have: \[ 4050 = C \times 0.015 \] ### Step 5: Solve for capital Now, we can solve for \(C\): \[ C = \frac{4050}{0.015} \] Calculating this gives: \[ C = 4050 \div 0.015 = 270000 \] ### Final Answer Thus, the capital is Rs. 270,000. ---
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