The position of the digit of a two digit number are interchanged. If the sum of the original number and the number obtained by interchanging the digit is 44. What is the sum of digit of that number ?

Explanation

Let the number is `therefore` Number obtained by interchaning its both digits
10b+a
`therefore`From the question,
10a + b + 10b + a = 44
11a + 11b = 44
`a+b=44/11=4`
Hence, sum of the two
digits = 4