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What will be the probability that an ordinary year has 53 Sunday?

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When the year is not a leap year. It has 52 complete weeks and 1 more day that can be {Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday} n (S) = 7.Out of these 7 cases, cases favourable for one more Sunday is-
{Sunday}, n (E) = 1
`therefore P (E) = 1/7`
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