A bag contains 3 red, 5 yellow and 4 green balls. 3 balls are drawn randomly. What is the probability that the balls drawn contain no yellow ball ?

Explanation

Total no. of ballsn (S) = `^12C_3`
`=(12 xx 11 xx 10)/(3 xx 2)`3 balls can be selected from 3 (red) + 4 (green)
= 7 balls`n(E) = ^7C_3= 7xx 6 xx 53 xx 2 = 35`
`therefore P (E) = 35/220 = 7/44`