Home
Class 14
MATHS
22,33,66,99,121,279,594...

22,33,66,99,121,279,594

A

33

B

121

C

279

D

594

Text Solution

AI Generated Solution

The correct Answer is:
To determine the odd one out in the series 22, 33, 66, 99, 121, 279, and 594, we can analyze the numbers in terms of their divisibility by 11. ### Step-by-Step Solution: 1. **Identify the Numbers**: The numbers in the series are 22, 33, 66, 99, 121, 279, and 594. 2. **Check Divisibility by 11**: - **22**: \(22 \div 11 = 2\) (Divisible) - **33**: \(33 \div 11 = 3\) (Divisible) - **66**: \(66 \div 11 = 6\) (Divisible) - **99**: \(99 \div 11 = 9\) (Divisible) - **121**: \(121 \div 11 = 11\) (Divisible) - **279**: \(279 \div 11 = 25.36\) (Not Divisible) - **594**: \(594 \div 11 = 54\) (Divisible) 3. **Identify the Odd One Out**: From the above calculations, we can see that all the numbers except 279 are divisible by 11. Therefore, 279 is the odd one out in this series. ### Conclusion: The odd one out in the series is **279**.
Promotional Banner

Topper's Solved these Questions

  • NUMBERS

    UPKAR PUBLICATION |Exercise QUESTION BANK |74 Videos
  • PARTNERSHIP

    UPKAR PUBLICATION |Exercise QUESTION BANK|49 Videos

Similar Questions

Explore conceptually related problems

Let R={(3,3),(6,6),(9,9),(12,12),(6,12),(3,9(,(3,12),(3,6)} be relation on the set A={3,6,9,12} . The relation is-

Let R={(3,3),(6,6),(9,9),(12,12),(6,12),(3,9),(3,12),(3,6)} be a relation on the set A={3,6,9,12} be a relation on the set A={3,6,9,12}. The relation is

The scores (out of 100) obtained by 33 students in a mathematics test are as follows 69.48.84,58,48,73,83,48,66,58,84,66,64,71,64,66,69,66,83,66,69,71,81,71,73,69,66,66,64,58,64,69,69. Represent this data in the form of a frequency distribution.

Represent the following set in Descriptive and Set-builder forms. {11, 22, 33, 44, 55, 66, 77, 88, 99}

33, 88, 121, 187, 287, 341

Transform [[1,-1,22,1,33,1,33,2,4]] into an upper transformations