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The true discount on a certain sum of mo...

The true discount on a certain sum of money due after 2 `1/2` years at `6%` per annum is less than the simple interest on the same sum for the same time by Rs. 81. Find the sum-

A

Rs. 4140

B

Rs. 4240

C

Rs. 4150

D

Rs. 4250

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The correct Answer is:
To solve the problem step by step, we need to find the sum of money based on the given conditions about true discount and simple interest. Let's break it down: ### Step 1: Understand the Terms - **True Discount (TD)**: The difference between the present value (PV) and the future value (FV) of a sum of money due at a certain time. - **Simple Interest (SI)**: The interest calculated on the principal amount over a period of time. ### Step 2: Set Up the Given Information - Time (T) = 2.5 years - Rate (R) = 6% per annum - The difference between Simple Interest and True Discount = Rs. 81 ### Step 3: Define the Variables Let the sum of money (Principal) be \( P \). ### Step 4: Calculate Simple Interest The formula for Simple Interest is: \[ SI = \frac{P \times R \times T}{100} \] Substituting the values: \[ SI = \frac{P \times 6 \times 2.5}{100} = \frac{15P}{100} = 0.15P \] ### Step 5: Calculate True Discount The True Discount can be calculated using the formula: \[ TD = \frac{SI \times R \times T}{100 + R \times T} \] Where \( R \times T = 6 \times 2.5 = 15 \). So, \[ TD = \frac{SI \times 15}{100 + 15} = \frac{SI \times 15}{115} \] Substituting \( SI = 0.15P \): \[ TD = \frac{0.15P \times 15}{115} = \frac{2.25P}{115} \] ### Step 6: Set Up the Equation According to the problem, the difference between SI and TD is Rs. 81: \[ SI - TD = 81 \] Substituting the values: \[ 0.15P - \frac{2.25P}{115} = 81 \] ### Step 7: Simplify the Equation To solve for \( P \), we need a common denominator: \[ 0.15P = \frac{15P}{100} = \frac{15P \times 115}{11500} = \frac{1725P}{11500} \] Now the equation becomes: \[ \frac{1725P}{11500} - \frac{2.25P}{115} = 81 \] Convert \( \frac{2.25P}{115} \) to have the same denominator: \[ \frac{2.25P \times 100}{11500} = \frac{225P}{11500} \] Now the equation is: \[ \frac{1725P - 225P}{11500} = 81 \] \[ \frac{1500P}{11500} = 81 \] ### Step 8: Solve for \( P \) Cross-multiplying gives: \[ 1500P = 81 \times 11500 \] Calculating the right side: \[ 1500P = 931500 \] Now divide both sides by 1500: \[ P = \frac{931500}{1500} = 621 \] ### Final Answer The sum of money is Rs. 621. ---
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