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The present worth of a sum due sometimes...

The present worth of a sum due sometimes hence is Rs. 576 and the banker's gain is Rs. 1. The true discount is-----

A

Rs. 16

B

Rs. 18

C

Rs. 24

D

Rs. 32

Text Solution

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The correct Answer is:
To solve the problem step by step, we will use the given information and the formula for true discount. ### Step 1: Identify the given values - Present Worth (PW) = Rs. 576 - Banker's Gain (BG) = Rs. 1 ### Step 2: Understand the relationship between True Discount (TD), Present Worth (PW), and Banker's Discount (BD) The formula for True Discount (TD) is: \[ TD = \sqrt{PW \times BD} \] Where: - PW = Present Worth - BD = Banker's Discount ### Step 3: Relate Banker's Gain (BG) to Banker's Discount (BD) Banker's Gain (BG) is defined as: \[ BG = BD - TD \] From the problem, we know: \[ BG = 1 \] So we can express Banker's Discount (BD) as: \[ BD = TD + 1 \] ### Step 4: Substitute the expression for BD into the True Discount formula Now we can substitute \( BD \) in the True Discount formula: \[ TD = \sqrt{PW \times (TD + 1)} \] ### Step 5: Substitute the value of Present Worth (PW) Now, substituting the value of PW: \[ TD = \sqrt{576 \times (TD + 1)} \] ### Step 6: Square both sides to eliminate the square root Squaring both sides gives: \[ TD^2 = 576 \times (TD + 1) \] ### Step 7: Rearranging the equation This expands to: \[ TD^2 = 576 \times TD + 576 \] Rearranging gives: \[ TD^2 - 576 \times TD - 576 = 0 \] ### Step 8: Solve the quadratic equation We can use the quadratic formula \( TD = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \) where \( a = 1, b = -576, c = -576 \): - Calculate the discriminant: \[ b^2 - 4ac = (-576)^2 - 4 \times 1 \times (-576) \] \[ = 331776 + 2304 = 334080 \] - Now apply the quadratic formula: \[ TD = \frac{576 \pm \sqrt{334080}}{2} \] ### Step 9: Calculate the square root and find TD Calculating \( \sqrt{334080} \) gives approximately 578. Thus: \[ TD = \frac{576 \pm 578}{2} \] Calculating the two possible values: 1. \( TD = \frac{1154}{2} = 577 \) (not valid, as it exceeds PW) 2. \( TD = \frac{-2}{2} = -1 \) (not valid) ### Step 10: Find the True Discount using the earlier method From earlier steps, we can also directly calculate True Discount using: \[ TD = \sqrt{576 \times 1} = \sqrt{576} = 24 \] ### Final Answer The True Discount is Rs. 24. ---
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