Monika deposits Rs. 8000 partly at `10%` and partly at `15%` interest for one year in a bank. If she gets an interest of Rs. 950 at the end of one year the amount deposits at `15%` is-

Options

A. Rs. 3000 less than deposited at `10%`
B. Rs. 1250 less than deposited at `10%`
C. Rs. 500 less than deposited at `10%`
D. Rs. 1500 less than deposited at `10%`

Answer

To solve the problem, we need to determine how much Monika deposited at 15% interest. Let's denote the amount deposited at 10% as \( x \) and the amount deposited at 15% as \( 8000 - x \).

### Step-by-Step Solution:

1. **Define Variables:**
Let the amount deposited at 10% be \( x \).
Therefore, the amount deposited at 15% will be \( 8000 - x \).

2. **Calculate Interest from Each Deposit:**
The interest earned from the amount deposited at 10% for one year is:
\[ \text{Interest at 10%} = \frac{10}{100} \times x = 0.1x \]
The interest earned from the amount deposited at 15% for one year is:
\[ \text{Interest at 15%} = \frac{15}{100} \times (8000 - x) = 0.15(8000 - x) \]

3. **Set Up the Equation:**
According to the problem, the total interest earned from both deposits is Rs. 950. Therefore, we can set up the equation:
\[ 0.1x + 0.15(8000 - x) = 950 \]

4. **Simplify the Equation:**
First, distribute the \( 0.15 \):
\[ 0.1x + 1200 - 0.15x = 950 \]
Combine like terms:
\[ -0.05x + 1200 = 950 \]

5. **Isolate \( x \):**
Subtract 1200 from both sides:
\[ -0.05x = 950 - 1200 \]
\[ -0.05x = -250 \]
Now, divide both sides by -0.05:
\[ x = \frac{-250}{-0.05} = 5000 \]

6. **Calculate the Amount Deposited at 15%:**
Now, substitute \( x \) back to find the amount deposited at 15%:
\[ \text{Amount at 15%} = 8000 - x = 8000 - 5000 = 3000 \]

### Final Answer:
The amount deposited at 15% is **Rs. 3000**.