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A man travels a certain distance at the ...

A man travels a certain distance at the rate of 12 km/hr and return back to the starting point at the rate of 15 km/hr . His average speed during the whole journey is

A

`13.5` km/hr

B

`13 1/3` km/hr

C

`12 2/3` km/hr

D

`14` km/hr

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The correct Answer is:
To find the average speed of the man during his entire journey, we can follow these steps: ### Step 1: Define the distance Let the distance from point A to point B be \( x \) km. ### Step 2: Calculate total distance The total distance traveled by the man is the distance from A to B and back from B to A. Therefore, the total distance \( D \) is: \[ D = x + x = 2x \text{ km} \] ### Step 3: Calculate time taken for each part of the journey 1. **Time taken to travel from A to B** at 12 km/hr: \[ T_1 = \frac{x}{12} \text{ hours} \] 2. **Time taken to return from B to A** at 15 km/hr: \[ T_2 = \frac{x}{15} \text{ hours} \] ### Step 4: Calculate total time taken The total time \( T \) for the entire journey is the sum of the time taken for each part: \[ T = T_1 + T_2 = \frac{x}{12} + \frac{x}{15} \] ### Step 5: Find a common denominator to add the times The least common multiple (LCM) of 12 and 15 is 60. We convert each fraction: \[ T = \frac{5x}{60} + \frac{4x}{60} = \frac{9x}{60} = \frac{3x}{20} \text{ hours} \] ### Step 6: Calculate average speed The average speed \( V \) is defined as total distance divided by total time: \[ V = \frac{D}{T} = \frac{2x}{\frac{3x}{20}} = 2x \times \frac{20}{3x} \] Here, \( x \) cancels out: \[ V = \frac{40}{3} \text{ km/hr} \] ### Step 7: Convert to mixed number To convert \( \frac{40}{3} \) into a mixed number: \[ \frac{40}{3} = 13 \frac{1}{3} \text{ km/hr} \] ### Final Answer The average speed during the whole journey is: \[ \text{Average Speed} = 13 \frac{1}{3} \text{ km/hr} \] ---
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