Home
Class 14
MATHS
40932div?+20=sqrt(15876) +39...

`40932div?+20=sqrt(15876) +39`

A

(282)42/145

B

(280(42/145)

C

(281)42/145

D

283

Text Solution

AI Generated Solution

The correct Answer is:
To solve the equation \( \frac{40932}{?} + 20 = \sqrt{15876} + 39 \), we will follow these steps: ### Step 1: Simplify the right side of the equation First, we need to calculate \( \sqrt{15876} \). \[ \sqrt{15876} = 126 \] Now, substituting this back into the equation gives us: \[ \frac{40932}{?} + 20 = 126 + 39 \] ### Step 2: Simplify further Now, we can simplify the right side: \[ 126 + 39 = 165 \] So, we have: \[ \frac{40932}{?} + 20 = 165 \] ### Step 3: Isolate the fraction Next, we will isolate the fraction by subtracting 20 from both sides: \[ \frac{40932}{?} = 165 - 20 \] Calculating the right side: \[ 165 - 20 = 145 \] Thus, we have: \[ \frac{40932}{?} = 145 \] ### Step 4: Solve for the question mark Now, we can solve for the question mark (let's denote it as \( x \)): \[ 40932 = 145 \times x \] To find \( x \), we divide both sides by 145: \[ x = \frac{40932}{145} \] ### Step 5: Perform the division Now, we calculate \( \frac{40932}{145} \): \[ 40932 \div 145 = 282 \] So, the value of the question mark is: \[ ? = 282 \] ### Final Answer The value of the question mark is \( 282 \). ---
Promotional Banner

Topper's Solved these Questions

  • MISCELLANEOUS EXERCISE -II

    UPKAR PUBLICATION |Exercise QUESTION BANK |88 Videos
  • MISCELLANEOUS EXERCISE -VI

    UPKAR PUBLICATION |Exercise QUESTION BANK |62 Videos

Similar Questions

Explore conceptually related problems

(3584 div 32)-11=sqrt(?)

754 div sqrt(4136) times 24=?

3sqrt(512)+2(2)/(5)div x=sqrt(25xx16)

3sqrt(512)div 4sqrt(16)div sqrt(576)=?

sqrt(1521)div3xx12=?

(79210 div 1780)-5.5=sqrt(?)

sqrt(289) div sqrt(x) = 1/5 , then the value of x is :

Let x =( sqrt1875/sqrt3888 div sqrt1200/ sqrt768)xx sqrt175/sqrt1792 . Then sqrtx is equal to: माना x =( sqrt1875/sqrt3888 div sqrt1200/ sqrt768)xx sqrt175/sqrt1792 तो sqrtx का मान ज्ञात कीजिए?

Simplify the following (i) sqrt45-3sqrt20+4sqrt5 (ii) sqrt(24)/8 + sqrt54/9 (iii) root4(12) xx root7(6) (iv) 4sqrt28 div 3sqrt7 div root3(7) (v) 3sqrt3+2sqrt27 + 7/(sqrt3) (vi) (sqrt3-sqrt2)^(2) (vii) root4(81)-8root3(216)+15root5(32)+ sqrt225 (viii) 3/sqrt8+ 1 / sqrt2 (ix) (2sqrt3)/3- (sqrt3)/6