In a school there are `40` students in class 8th, `80%` of them passed and there are `60` students in class 9th, `60%` of them passed. What is the total pass percentage of both the classes ?

Options

A. `75%`
B. `68%`
C. `72%`
D. `77%`

Answer

To find the total pass percentage of both classes, we can follow these steps:

### Step 1: Calculate the number of students who passed in class 8.
- Total students in class 8 = 40
- Percentage of students who passed = 80%

To find the number of students who passed:
\[ \text{Number of students passed in class 8} = \frac{80}{100} \times 40 = 32 \]

### Step 2: Calculate the number of students who passed in class 9.
- Total students in class 9 = 60
- Percentage of students who passed = 60%

To find the number of students who passed:
\[ \text{Number of students passed in class 9} = \frac{60}{100} \times 60 = 36 \]

### Step 3: Calculate the total number of students in both classes.
\[ \text{Total students} = \text{Students in class 8} + \text{Students in class 9} = 40 + 60 = 100 \]

### Step 4: Calculate the total number of students who passed in both classes.
\[ \text{Total passed} = \text{Students passed in class 8} + \text{Students passed in class 9} = 32 + 36 = 68 \]

### Step 5: Calculate the total pass percentage.
The total pass percentage is calculated using the formula:
\[ \text{Total pass percentage} = \left( \frac{\text{Total passed}}{\text{Total students}} \right) \times 100 \]
Substituting the values:
\[ \text{Total pass percentage} = \left( \frac{68}{100} \right) \times 100 = 68\% \]

### Final Answer:
The total pass percentage of both classes is **68%**.

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