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What will come in the place of question mark(?) in each of the following question ?
`(0.bar6+0.bar7+0.bar5+0.bar4)`=?

A

`4 1/4`

B

`3/9`

C

2

D

`2 4/9`

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The correct Answer is:
To solve the expression \(0.\overline{6} + 0.\overline{7} + 0.\overline{5} + 0.\overline{4}\), we will convert each repeating decimal into a fraction. ### Step 1: Convert \(0.\overline{6}\) to a fraction Let \(x = 0.\overline{6}\). Multiplying both sides by 10: \[ 10x = 6.\overline{6} \] Now, subtract the original equation from this new equation: \[ 10x - x = 6.\overline{6} - 0.\overline{6} \] \[ 9x = 6 \] \[ x = \frac{6}{9} = \frac{2}{3} \] ### Step 2: Convert \(0.\overline{7}\) to a fraction Let \(y = 0.\overline{7}\). Multiplying both sides by 10: \[ 10y = 7.\overline{7} \] Subtracting the original equation: \[ 10y - y = 7.\overline{7} - 0.\overline{7} \] \[ 9y = 7 \] \[ y = \frac{7}{9} \] ### Step 3: Convert \(0.\overline{5}\) to a fraction Let \(z = 0.\overline{5}\). Multiplying both sides by 10: \[ 10z = 5.\overline{5} \] Subtracting the original equation: \[ 10z - z = 5.\overline{5} - 0.\overline{5} \] \[ 9z = 5 \] \[ z = \frac{5}{9} \] ### Step 4: Convert \(0.\overline{4}\) to a fraction Let \(w = 0.\overline{4}\). Multiplying both sides by 10: \[ 10w = 4.\overline{4} \] Subtracting the original equation: \[ 10w - w = 4.\overline{4} - 0.\overline{4} \] \[ 9w = 4 \] \[ w = \frac{4}{9} \] ### Step 5: Add all the fractions together Now we can add all the fractions: \[ 0.\overline{6} + 0.\overline{7} + 0.\overline{5} + 0.\overline{4} = \frac{2}{3} + \frac{7}{9} + \frac{5}{9} + \frac{4}{9} \] First, convert \(\frac{2}{3}\) to a fraction with a denominator of 9: \[ \frac{2}{3} = \frac{2 \times 3}{3 \times 3} = \frac{6}{9} \] Now add: \[ \frac{6}{9} + \frac{7}{9} + \frac{5}{9} + \frac{4}{9} = \frac{6 + 7 + 5 + 4}{9} = \frac{22}{9} \] ### Final Answer Thus, the value of \(0.\overline{6} + 0.\overline{7} + 0.\overline{5} + 0.\overline{4}\) is: \[ \frac{22}{9} \]
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