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A trader allows two successive discount ...

A trader allows two successive discount of `20%` and `10%`. If he gets Rs. 108 for an article, then its marked price is

A

Rs. `142 cdot 56`

B

Rs. `140 cdot 40`

C

Rs. 160

D

Rs. 150

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The correct Answer is:
To find the marked price of the article after allowing two successive discounts of 20% and 10%, we can follow these steps: ### Step 1: Calculate the net discount percentage The formula for calculating the net discount when two successive discounts are applied is: \[ \text{Net Discount} = x + y - \frac{xy}{100} \] where \(x\) is the first discount percentage and \(y\) is the second discount percentage. Here, \(x = 20\%\) and \(y = 10\%\). Substituting the values: \[ \text{Net Discount} = 20 + 10 - \frac{20 \times 10}{100} \] \[ = 30 - \frac{200}{100} \] \[ = 30 - 2 = 28\% \] ### Step 2: Determine the selling price after the discount Let the marked price be \(M\). After applying a 28% discount, the selling price (SP) can be expressed as: \[ \text{SP} = M - \text{Discount} \] \[ \text{SP} = M - 0.28M = 0.72M \] ### Step 3: Set up the equation with the given selling price We know from the problem that the selling price (SP) is Rs. 108. Therefore, we can set up the equation: \[ 0.72M = 108 \] ### Step 4: Solve for the marked price \(M\) To find \(M\), we can rearrange the equation: \[ M = \frac{108}{0.72} \] Calculating the right side: \[ M = \frac{108 \times 100}{72} = \frac{10800}{72} = 150 \] ### Conclusion The marked price of the article is Rs. 150. ---
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