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P can complete a work in 15 days.Q can c...

P can complete a work in 15 days.Q can complete the same work in 10 days ,P started working and after 5 days Q joined him. How many days more will they take to complete the remaining work ?

A

1 days

B

2 days

C

3 days

D

4 days

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to follow these steps: ### Step 1: Determine the work done by P and Q in one day. - P can complete the work in 15 days. Therefore, the work done by P in one day is: \[ \text{Work done by P in 1 day} = \frac{1}{15} \] - Q can complete the work in 10 days. Therefore, the work done by Q in one day is: \[ \text{Work done by Q in 1 day} = \frac{1}{10} \] ### Step 2: Calculate the work done by P in the first 5 days. - In 5 days, the work done by P is: \[ \text{Work done by P in 5 days} = 5 \times \frac{1}{15} = \frac{5}{15} = \frac{1}{3} \] ### Step 3: Determine the remaining work after P has worked for 5 days. - The total work is considered as 1 unit. Therefore, the remaining work after P has completed \(\frac{1}{3}\) of the work is: \[ \text{Remaining work} = 1 - \frac{1}{3} = \frac{2}{3} \] ### Step 4: Calculate the combined work done by P and Q in one day. - When Q joins P, their combined work done in one day is: \[ \text{Combined work} = \text{Work done by P in 1 day} + \text{Work done by Q in 1 day} = \frac{1}{15} + \frac{1}{10} \] - To add these fractions, we need a common denominator. The least common multiple of 15 and 10 is 30. Therefore: \[ \frac{1}{15} = \frac{2}{30}, \quad \frac{1}{10} = \frac{3}{30} \] \[ \text{Combined work} = \frac{2}{30} + \frac{3}{30} = \frac{5}{30} = \frac{1}{6} \] ### Step 5: Calculate the number of days required to complete the remaining work. - The remaining work is \(\frac{2}{3}\). To find out how many days it will take for P and Q to complete this remaining work, we can set up the equation: \[ \text{Days required} = \frac{\text{Remaining work}}{\text{Combined work per day}} = \frac{\frac{2}{3}}{\frac{1}{6}} \] - Dividing by a fraction is the same as multiplying by its reciprocal: \[ \text{Days required} = \frac{2}{3} \times 6 = 4 \] ### Conclusion P and Q will take **4 more days** to complete the remaining work. ---
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