`cos^2θ`` -` `sinθ` `- ``1/4`=0

The values of θ lying between 0 and π/2 and satisfying the equation ∣ 1+sin ^2θ sin^2θ sin^2θ cos^2θ 1+cos^2θ cos^2θ 4sin4θ 4sin4θ 1+4sin4θ ∣ =0 are

The maximum value of Δ= ∣ ∣ ∣ ​ 1 1 1+cosθ ​ 1 1+sinθ 1 ​ 1 1 1 ∣ ​ is (θ is real number )

cosθ/ (1-tanθ) + sinθ/ (1−cotθ) is equals to ​

if x =a cos^3θ and y=b sin^3θ then prove that: ( frac{x}{a} )^ 2/3

tan θ =-4/3 , sin θ is

Prove: sin^2θ + cos^2θ =1

The number of solutions of the pair of equations 2sin^2theta−cos2theta=0 and 2cos ^2 θ−3sinθ=0 in the interval [0,2π] is :

The number of all possible values of θ where 0 sin3θ = 2cos((3θ)/y )+ 2sin((3θ)/z) (xyz)sin3θ = (y + 2z)cos3θ + ysin3θ has a solution (x_0,y_0,z_0) with y_0 ,z_0 ≠ 0, is

In the following figure all surfaces are smooth. The system is released from rest , then A. acceleration of wedge greater then g tanθ B. acceleration of m is g√(1+2cos⁡^2θ) C. acceleration of m is g D. acceleration of wedge is g sinθ

cosα+cosβ= 3/2 ​ and sinα+sinβ= 1/2 ​ and θ is the arithmetic mean of α and β, then sin2θ+cos2θ is equal to Yes No