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If (x+y)^(m+n)=x^my^n then dy/dx= (A) ...

If `(x+y)^(m+n)=x^my^n` then `dy/dx=`
(A) `x/y`
(B) `-y/x`
(C) `-x/y`
(D) `y/x`

Answer

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  • If x^(n) y^(n) =(x+y) ^(n),then (dy)/(dx)=

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    xy
  • If x ^(n) y^(n) =( x+y ) ^(n),then (dy)/(dx)=

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    ` (-1)/( (x-1)^(2))`
    B
    ` (1)/( ( x-1)^(2))`
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