The cathode production of the electrolysis of zinc iodide is :

Options

A. Iodine
B. Zinc
C. Zinc oxide
D. Chloride

Explanation

To find the cathode product of the electrolysis of zinc iodide (ZnI₂), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Electrolyte**: The electrolyte in this case is zinc iodide (ZnI₂). When dissolved in water or molten, it dissociates into its ions: Zn²⁺ and I⁻.

2. **Set Up the Electrolysis**: In an electrolytic cell, there are two electrodes: anode (positive) and cathode (negative). The anode is connected to the positive terminal of the battery, and the cathode is connected to the negative terminal.

3. **Ion Migration**: During electrolysis, the positively charged ions (Zn²⁺) migrate towards the cathode, while the negatively charged ions (I⁻) migrate towards the anode.

4. **Oxidation at the Anode**: At the anode, the I⁻ ions undergo oxidation. Each iodide ion loses an electron and forms iodine (I₂):
\[ 2 I⁻ \rightarrow I₂ + 2 e⁻ \]

5. **Reduction at the Cathode**: At the cathode, the Zn²⁺ ions undergo reduction. Each Zn²⁺ ion gains two electrons to form solid zinc (Zn):
\[ Zn^{2+} + 2 e⁻ \rightarrow Zn \]

6. **Conclusion**: Thus, the product formed at the cathode during the electrolysis of zinc iodide is solid zinc (Zn).

### Final Answer:
The cathode product of the electrolysis of zinc iodide is solid zinc (Zn).

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