Study the given figure and answer the question that follow:

Write the equation representing the reaction that occurs.

Options

A. At the Cathode: `Cu - 2e^(-) to Cu^(2+)`
At the Anode `Cu^(2+) + 2e^(-) to Cu `
B. At the Cathode : `Cu^+ + 2e^(-) to Cu `
At the Anode : `Cu^(2+) - 2e^(-) to Cu^(2+)`
C. Both (a) and (b)
D. At the Cathode : `Cu^(2+) + 2e^(-) to Cu`
At the Anode : `Cu - 2e^(-) to Cu^(2+)`

Answer

D

Explanation

Electrode on the left side is the oxidising electrode because anode is always connected to positive terminal of the battery, where copper atoms lose electrons at this electrode.