Which of the following is obtained at anode during the electrolysis of lead bromide ?

Options

A. Pb
B. `Br_2`
C. Both 1 and 2
D. None of these

Explanation

To determine which substance is obtained at the anode during the electrolysis of lead bromide (PbBr2), we can follow these steps:

### Step 1: Identify the Electrolyte
Lead bromide (PbBr2) is the electrolyte used in the electrolysis process. It dissociates into its ions when molten or dissolved in water.

**Hint:** Remember that electrolytes break down into positive and negative ions during electrolysis.

### Step 2: Write the Dissociation Equation
When lead bromide is molten, it dissociates into lead ions (Pb²⁺) and bromide ions (Br⁻):
\[ \text{PbBr}_2 \rightarrow \text{Pb}^{2+} + 2\text{Br}^- \]

**Hint:** Always write the dissociation equation to understand the ions involved in the electrolysis.

### Step 3: Identify the Electrodes
In electrolysis, there are two electrodes: the anode (positive electrode) and the cathode (negative electrode). The anode attracts the negative ions (anions), while the cathode attracts the positive ions (cations).

**Hint:** Remember that anions move towards the anode and cations move towards the cathode.

### Step 4: Determine the Reactions at Each Electrode
At the anode, oxidation occurs. The bromide ions (Br⁻) will lose electrons and be oxidized to form bromine gas (Br₂):
\[ 2\text{Br}^- \rightarrow \text{Br}_2 + 2e^- \]

At the cathode, the lead ions (Pb²⁺) will gain electrons and be reduced to form lead metal (Pb):
\[ \text{Pb}^{2+} + 2e^- \rightarrow \text{Pb} \]

**Hint:** Oxidation involves the loss of electrons, while reduction involves the gain of electrons.

### Step 5: Conclusion
From the above reactions, we can conclude that bromine gas (Br₂) is produced at the anode during the electrolysis of lead bromide.

**Final Answer:** Br₂ (bromine gas) is obtained at the anode during the electrolysis of lead bromide.

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