A chloride which forms a precipitate that is soluble in excess of ammonium hydroxide is :

Options

A. Calcium chloride
B. Ferrous chloride
C. Ferric chloride
D. Copper chloride

Explanation

To solve the question "A chloride which forms a precipitate that is soluble in excess of ammonium hydroxide is:", we can follow these steps:

### Step 1: Understand the Question
We need to identify a chloride compound that forms a precipitate when reacted with ammonium hydroxide (NH4OH) and that this precipitate is soluble in excess ammonium hydroxide.

### Step 2: Identify Common Chlorides
Common chlorides include:
- Ferrous chloride (FeCl2)
- Ferric chloride (FeCl3)
- Copper(II) chloride (CuCl2)
- Calcium chloride (CaCl2)

### Step 3: React Each Chloride with Ammonium Hydroxide
1. **Ferrous Chloride (FeCl2)**:
- When FeCl2 reacts with NH4OH, it forms ferrous hydroxide (Fe(OH)2) as a precipitate.
- Fe(OH)2 is not soluble in excess NH4OH.

2. **Ferric Chloride (FeCl3)**:
- When FeCl3 reacts with NH4OH, it forms ferric hydroxide (Fe(OH)3) as a precipitate.
- Fe(OH)3 is also not soluble in excess NH4OH.

3. **Copper(II) Chloride (CuCl2)**:
- When CuCl2 reacts with NH4OH, it forms copper(II) hydroxide (Cu(OH)2) as a precipitate.
- Cu(OH)2 is initially insoluble, but when excess NH4OH is added, it forms a soluble complex, tetraamminecopper(II) chloride ([Cu(NH3)4]Cl2).

4. **Calcium Chloride (CaCl2)**:
- When CaCl2 reacts with NH4OH, it forms calcium hydroxide (Ca(OH)2).
- Ca(OH)2 is not soluble in excess NH4OH.

### Step 4: Conclusion
From the analysis, the only chloride that forms a precipitate which is soluble in excess of ammonium hydroxide is **Copper(II) Chloride (CuCl2)**.

### Final Answer
The chloride which forms a precipitate that is soluble in excess of ammonium hydroxide is **Copper(II) Chloride (CuCl2)**.

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