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3 5/6+6 1/7 - 2 1/3 - 1 1/2=...

`3 5/6+6 1/7 - 2 1/3 - 1 1/2=`

A

`6 1/7`

B

`6 1/21

C

`6 5/28`

D

`6 1/14`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \( 3 \frac{5}{6} + 6 \frac{1}{7} - 2 \frac{1}{3} - 1 \frac{1}{2} \), we will follow these steps: ### Step 1: Convert Mixed Numbers to Improper Fractions First, we convert each mixed number to an improper fraction. 1. \( 3 \frac{5}{6} = \frac{3 \times 6 + 5}{6} = \frac{18 + 5}{6} = \frac{23}{6} \) 2. \( 6 \frac{1}{7} = \frac{6 \times 7 + 1}{7} = \frac{42 + 1}{7} = \frac{43}{7} \) 3. \( 2 \frac{1}{3} = \frac{2 \times 3 + 1}{3} = \frac{6 + 1}{3} = \frac{7}{3} \) 4. \( 1 \frac{1}{2} = \frac{1 \times 2 + 1}{2} = \frac{2 + 1}{2} = \frac{3}{2} \) Now, we rewrite the expression: \[ \frac{23}{6} + \frac{43}{7} - \frac{7}{3} - \frac{3}{2} \] ### Step 2: Find a Common Denominator Next, we need to find a common denominator for the fractions. The denominators are 6, 7, 3, and 2. The least common multiple (LCM) of these numbers is 42. ### Step 3: Convert Each Fraction to the Common Denominator Now we convert each fraction to have a denominator of 42: 1. \( \frac{23}{6} = \frac{23 \times 7}{6 \times 7} = \frac{161}{42} \) 2. \( \frac{43}{7} = \frac{43 \times 6}{7 \times 6} = \frac{258}{42} \) 3. \( \frac{7}{3} = \frac{7 \times 14}{3 \times 14} = \frac{98}{42} \) 4. \( \frac{3}{2} = \frac{3 \times 21}{2 \times 21} = \frac{63}{42} \) ### Step 4: Rewrite the Expression Now we can rewrite the expression with the common denominator: \[ \frac{161}{42} + \frac{258}{42} - \frac{98}{42} - \frac{63}{42} \] ### Step 5: Combine the Fractions Combine the fractions: \[ \frac{161 + 258 - 98 - 63}{42} = \frac{258}{42} \] ### Step 6: Simplify the Result Now simplify \( \frac{258}{42} \): - The greatest common divisor (GCD) of 258 and 42 is 6. - Divide both the numerator and the denominator by 6: \[ \frac{258 \div 6}{42 \div 6} = \frac{43}{7} \] ### Step 7: Convert Back to Mixed Number Finally, convert \( \frac{43}{7} \) back to a mixed number: - \( 43 \div 7 = 6 \) remainder \( 1 \), so it becomes \( 6 \frac{1}{7} \). Thus, the final answer is: \[ \boxed{6 \frac{1}{7}} \]
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