The number of consecutive zeros in `2^3xx3^4xx5^4xx7` is equal to:

Options

A. 2
B. 3
C. 4
D. 5

Answer

To find the number of consecutive zeros in the expression \(2^3 \times 3^4 \times 5^4 \times 7\), we need to determine how many times the number can be divided by 10. A trailing zero is produced by the factors of 10, which is the product of 2 and 5. Therefore, we need to find the minimum of the powers of 2 and 5 in the expression.

### Step-by-Step Solution:

1. **Identify the factors in the expression**:
The expression is \(2^3 \times 3^4 \times 5^4 \times 7\). Here, we have:
- The power of 2 is 3.
- The power of 5 is 4.
- The powers of 3 and 7 do not contribute to trailing zeros.

2. **Determine the number of pairs of 2 and 5**:
To form a trailing zero, we need one factor of 2 and one factor of 5. Therefore, we need to find the minimum of the powers of 2 and 5:
- Power of 2 = 3
- Power of 5 = 4

The number of pairs of (2, 5) that can be formed is given by:
\[ \text{Number of pairs} = \min(\text{Power of 2}, \text{Power of 5}) = \min(3, 4) = 3 \]

3. **Conclusion**:
Therefore, the number of consecutive zeros in the expression \(2^3 \times 3^4 \times 5^4 \times 7\) is **3**.

### Final Answer:
The number of consecutive zeros is **3**.