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Integrate the function: Sinx.Sin(Cosx)...

Integrate the function:
`Sinx.Sin(Cosx)`

Text Solution

Verified by Experts

Let` cosx=t`
differentiating both sides with respect to t we get
`-sinx=dt/dx`
`=dx=-dt/sinx`
So the given equation is
`∫sinxsin(cosx)dx`
Putting value of t we get `∫sinxsint*(dt/-sinx)`
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