(a) `3/6[...]5/6`
(b) `1/7[...]1/4`
(c) `4/5[...]5/5`
(d) `3/5[...]3/7`

Solve (a) 2/3 + 1/7 (b) 3/10 + 7/15 (c) 4/9 + 2/7 (d) 5/7 + 1/3 (e) 2/5 + 1/6 (f) 4/5 + 2/3 (g) (3/4) (1/3) (h) (5/6) (1/3) (1) 2/3 + 3/4 + 1/2 (1) 1/2 + 1/3 = 1/6 (k) (1) 1/3 + (3) 2/3 (1) (4) 2/3 +(3) 1/4 (m) ((16)/5))(7/5)

Express the following as improper fractions: (a) (7)(3)/(4) (b) (5)(6)/(7) (c) (2)(5)/(6) (d) (10)(3)/(5) (e) (9) (3)/(7) (f) (8)(9)/(4)

5/4-7/6-(-2)/3=\ 3/4 (b) -3/4 (-7)/(12) (d) 7/(12)

Simplify : (2(3)/(4))/(1(5)/(6)) +7/8 xx(1/3 + 1/4) + 5/7 + 3/4 of 3/7

(6)/(5-(5)/(3))+(4-(2)/(4-(1)/(2)))/(5-(3)/(2))-(2)/(5) of {(6)/(9)+(2)/(3) of (1)/(2)}=?( a) 1(1)/(3)( b) 2(13)/(49) (c) 1(7)/(16) (d) (3)/(5)

The value of 6 1/5-[4 1/2-{5/6-(3/5+3/10-7/15)} is 6 1/5-[4 1/2-{5/6-(3/5+3/10-7/15)} का मान क्या है ?

A=[[(2)/(3),1,(5)/(3)(1)/(3),(2)/(3),(4)/(3)(7)/(3),2,(2)/(3)]] and B=[[(2)/(5),(3)/(5),1(1)/(5),(2)/(5),(4)/(5)(7)/(5),(6)/(5),(2)/(5)]]

Multiply and express as a mixed fraction : (a) 3xx(5)(1)/(5) (b) 5xx(6)(3)/(4) (c) 7xx(2)(1)/(4) (d) 4xx(6)(1)/(3)( e) (3)(1)/(4)xx6( f )(3)(2)/(3)xx8