A particle starts moving with velocity "vecV=hat i(m/s)", and acceleration "vec a=(hat i+hat j)(m/s^(2))".Find the radius of curvature of the particle at "t=1sec".

A particle of mass 2sqrt(5) Kg is having velocity vec v=(2hat i+hat j)m/s " and acceleration vec a=(hat j-hat i)m/s^(2) " at some instant of time. At same instant find component of net force (in N) parallel to velocity.

A particle is moving in x-y plane. At an instant, it has velocity (4 hat (i) + 4 hat(j)) m//s and acceleration (3 hat(i) + 5 hat(j)) m//s^(2) At that instant, the radius of curvature of its path will be :

A particle has initial velocity vec(v)=3hat(i)+4hat(j) and a constant force vec(F)=4hat(i)-3hat(j) acts on the particle. The path of the particle is :

An alpha particle is moving with a velocity of (7 xx 10^(5) hat I m//s) in a magnetic field of (5 hat I + 9 hat j) T. Find the magnetic force acting on the particle.

An alpha particle is moving with a velocity of (7 xx 10^(5) hat i m//s) in a magnetic field of (5 hat i + 9 hat j ) . T . Find the magnetic force acting on the particle.

A particle has initial velocity of (3hat(i)+4hat(j)) m//s and a acceleration of (4hat(i)-3hat(j)) m//s^(2) . Its speed after one second will be equal to :-

A particle has initial velocity (3 hat i+ 4 hat j) and has acceleration (0.1 hat i+ 0.3 hat j) . Its speed after 10 s is.

Two particles of equal masses have velocities vec v_1 = 8 hat i and vec v_2 = 8 hat j . First particle has an acceleration vec a_1 = (5 hat i + 5 hat j) ms^(-2) while the acceleration of the other particle is zero. The centre of mass of the two particles moves is a path of

A particle is moving with a velocity of vec(v)=(3hat(i)+4that(j))m//s . Find the ratio of rangential acceleration to that of total acceleration at t=1sec