The refractive index of the material of a prism is 1.5 and its refracting angle is `6^o`. Find the deviation produced by the prism for a small angle of incidence.

The refractive index of the material of an equilateral prism is 1.6. The angle of minimum deviation due to the prism would be

(a) If the refracting angle of a prism is 60^@ and the minimum deviation is 30^@ , then find the angle of incidence. (b) A ray of light passes through an equilateral prism such that the angle of emergence is equal to the angle of incidence and each is equal to 3//4^(th) of the angle of prism. Find the angle of deviation. (c) The refracting of a prism is A and the refractive index of the material of the prism is cotA//2 . Find the angle of deviation. (d) The angle of a prism is 60^@ . What is the angle of incidence for minimum deviation? The refractive index of the material of the prism is sqrt2 .

The refractive index of the material of a prism of 60^(@) angle for yellow light is sqrt(2) . Calculate angle of minimum deviation, angle of incidence and angle of refraction.

A prism has refractive index sqrt((3)/(2)) and refractive angle 90^@ . Find the minimum deviation produced by prism

The refracting angle of a prism is A and refractive index of the material of the prism is cos(A//2) . The angle of minimum deviation is

There is prism of refractive index 1.5 and prism angle 2 degree . Find minimum deviation caused by this prism

The refracting angle of a prism is A, and refractive index of the material of the prism is cot (A)/(2) . The angle of minimum deviation is

The refracting angle of the prism is 60^@ and the refractive index of the material of the prism is sqrt(3) . Calculate the angle of minimum deviation in degree.

The refracting angle of a prism is A, and refractive index of the material of the prism is cot (A//2). the angel of minimum deviation is