1.Consider the situation shown in figure (6-E2).Calculate (a) the acceleration of the `1*0kg` blocks,(b) the tension in the string connecting the `1.0kg` blocks and (c) the tension in the string attached to `0.50kg`.

Consider the situation shown in figure. Calculate a. the acceleration of the 1.0 kg blocks, b. the tension in the strilng connecting the 1.0 kg blocks and c. the tension in the stting attached to 0.50 kg.

Consider the situation shown in figure .Both the pulleys and the string and light and all the surfaces are smooth. (a) Find the acceleration of 1kg block. (b) Find the tension in the string. (g = 10 m//s^(2)) .

In the diagram shown in figure, both pulleys and strings are massless. The acceleration of 2 kg block is

Consider the situation shown in the figure. The surface is smooth and the string and the pulley are light. Find the acceleration of each block and tension in the string.

If m_1 =10kg, m_2 = 4kg and m_3 = 2kg the tension in the string connecting m_1 and m_2 is,

In the arrangement shown in figure , find the ratio of tension in the strings attached with 4kg block and the with 1kg block

If the elevator in shown figure is moving upwards with constant acceleration 1 ms^(-2) , tension in the string connected to block A of mass 6 kg would be ( take, g =10 ms^(-2) )

A block of mass 30 kg is suspended by three string as shown in fig, Find the tension in each string.

In the figure shown ,find : (g = 10 m//s^(2)) (a) acceleration of 1 kg,2 kg and 3 kg blocks and (b) tension T_(1) and T_(2) .

A 4kg block is attached to a vertical rod by means of two strings of equal length. When the system rotates about the axis of the rod, the strings are extended as shown in figure. (a) How many revolutions per minute must the system make in order for the tension in the upper string to be 200N ? (b) What is the tension in the lower string then ?