9. `(dy)/(dx)=(y^(2)-y-2)/(x^(2)+2x-3)`

The family of curves represented by (dy)/(dx)=(x^(2)+x+1)/(y^(2)+y+1) and the family represented by (dy)/(dx)+(y^(2)+y+1)/(x^(2)+x+1)=0

The solution of the differential equation (dy)/(dx)=(3x^2y^4+2x y)/(x^2-2x^3y^3) is

Solve y-x(dy)/(dx)=a(y^(2)+(dy)/(dx))

x(dy)/(dx)+y=y^(2)x^(3)cos x

(dy)/(dx)+(x-2y)/(2x-y)=0

(dy)/(dx)=(x+y+1)/(2x+2y+3)

if y=ae^(x)+be^(-3x)+c , then the value of ((d^(3)y)/(dx^(3))+2(d^(2)y)/(dx^(2)))/((dy)/(dx)) is

dy/dx = (2x-y)/(x-2y)

dy/dx = (2x-y)/(x-2y)

Find the order and degree of the following differential equations. i) (dy)/(dx)+y=1/((dy)/(dx)) , ii) e^(e^(3)y)/(dx^(3))-x(d^(2)y)/(dx^(2))+y=0 , iii) sin^(-1)(dy)/(dx)=x+y , iv) log_(e)(dy)/(dx)=ax+by v) y(d^(2)y)/(dx^(2))+x((dy)/(dx))^(2)-4y(dy)/(dx)=0