`(1/3xx1/5)/(1/3xx1/5+1/3xx1/6+1/3xx1/7)`

1/3xx1/4xx1/3xx1/3

(1/4xx2/3)xx5/6=...xx(2/3xx5/6)

Simplify: ((13)/9xx(-15)/2)+\ (7/3xx8/5)+(3/5xx1/2)

Find the sum of infinite series (1)/(1xx3xx5)+(1)/(3xx5xx7)+(1)/(5xx7xx9)+….

1/2+1/3xx1/3-:2/3-1/2xx[1/3+{1/2-(2/3+1/2+1/3)}]

Simplify: (3/2xx1/6)+(5/3xx7/2)-\ ((13)/8xx4/3)

Find the sum 3/(1xx2)xx1/2+4/(2xx3)xx(1/2)^2+5/(3xx4)xx(1/2)^2+ ton terms.

Tell what property allows you to compute 1 /3 xx (6 xx 4/5) as ( 1/3 xx 6 ) xx 4/3.

If S=1/(1xx3xx5)+1/(3xx5xx7)+1/(5xx7xx9)+ddot to infinity, then find the value of [36 S] , where [.] represents the greatest integer function.

Simplify : ((-3)/2xx4/5)+(9/5xx(-10)/3)-(1/2xx3/4)