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Axx(B-C)=(AxxB)-(BxxC)...

`Axx(B-C)=(AxxB)-(BxxC)`

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If A={1,4}B={2,3,6} and C={2,3,7} verify that Axx(B-C)=(AxxB)-(AxxC) .

If A={2} , B={5} , C={3,4,6} , then verify that Axx(BnnC)=(AxxB)nn(AxxC) .

If A={1,2,3},B={4},C={5}, then verify that: Axx(BuuC)=(AxxB)uu(AxxC)

Theorem 1(i) (For any three set A;B;C ; prove that Axx(BuuC)=(AxxB)uu(AxxC))

Let A={1,2},\ B={1,2,3,4},\ C={5,6}a n d\ D={5,6,7,8} . Verity that: Axx(BnnC)=(AxxB)nn(AxxC)

If A={1,4},B={2,3,6} and C={2,3,7} , then verify that Axx(BcupC)=(AxxB)cup(AxxC)

If A={1,4},B={2,3,6} and C={2,3,7} , then verify that Axx(BcapC)=(AxxB)cap(AxxC)

Given A={1,2},B={3},C={4,5} , test whether the following is true: Axx(BcapC)=(AxxB)cap(AxxC)

Let A={1,2},B={1,2,3,4},C={5,6}and D={5,6,7,8}. Verify that: (i) Axx(B nn C)=(AxxB)nn(AxxC) . (ii) AxxC is a subset of BxxD .

If A={2,3},\ B={4,5},\ C={5,6},\ \ find Axx(BuuC),\ Axx(BnnC),\ (AxxB)uu(AxxC)dot